Optimal. Leaf size=144 \[ \frac {2 a^3 (5 B+i A) (c-i c \tan (e+f x))^{7/2}}{7 c^2 f}-\frac {8 a^3 (2 B+i A) (c-i c \tan (e+f x))^{5/2}}{5 c f}+\frac {8 a^3 (B+i A) (c-i c \tan (e+f x))^{3/2}}{3 f}-\frac {2 a^3 B (c-i c \tan (e+f x))^{9/2}}{9 c^3 f} \]
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Rubi [A] time = 0.20, antiderivative size = 144, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 43, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.047, Rules used = {3588, 77} \[ \frac {2 a^3 (5 B+i A) (c-i c \tan (e+f x))^{7/2}}{7 c^2 f}-\frac {8 a^3 (2 B+i A) (c-i c \tan (e+f x))^{5/2}}{5 c f}+\frac {8 a^3 (B+i A) (c-i c \tan (e+f x))^{3/2}}{3 f}-\frac {2 a^3 B (c-i c \tan (e+f x))^{9/2}}{9 c^3 f} \]
Antiderivative was successfully verified.
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Rule 77
Rule 3588
Rubi steps
\begin {align*} \int (a+i a \tan (e+f x))^3 (A+B \tan (e+f x)) (c-i c \tan (e+f x))^{3/2} \, dx &=\frac {(a c) \operatorname {Subst}\left (\int (a+i a x)^2 (A+B x) \sqrt {c-i c x} \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac {(a c) \operatorname {Subst}\left (\int \left (4 a^2 (A-i B) \sqrt {c-i c x}-\frac {4 a^2 (A-2 i B) (c-i c x)^{3/2}}{c}+\frac {a^2 (A-5 i B) (c-i c x)^{5/2}}{c^2}+\frac {i a^2 B (c-i c x)^{7/2}}{c^3}\right ) \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac {8 a^3 (i A+B) (c-i c \tan (e+f x))^{3/2}}{3 f}-\frac {8 a^3 (i A+2 B) (c-i c \tan (e+f x))^{5/2}}{5 c f}+\frac {2 a^3 (i A+5 B) (c-i c \tan (e+f x))^{7/2}}{7 c^2 f}-\frac {2 a^3 B (c-i c \tan (e+f x))^{9/2}}{9 c^3 f}\\ \end {align*}
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Mathematica [A] time = 8.95, size = 130, normalized size = 0.90 \[ -\frac {2 a^3 c \sec ^3(e+f x) \sqrt {c-i c \tan (e+f x)} (\cos (e-2 f x)-i \sin (e-2 f x)) ((81 A-62 i B) \tan (e+f x)+\cos (2 (e+f x)) ((81 A-97 i B) \tan (e+f x)-129 i A-113 B)+7 (B-12 i A))}{315 f (\cos (f x)+i \sin (f x))^3} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.93, size = 149, normalized size = 1.03 \[ \frac {\sqrt {2} {\left ({\left (1680 i \, A + 1680 \, B\right )} a^{3} c e^{\left (6 i \, f x + 6 i \, e\right )} + {\left (3024 i \, A + 1008 \, B\right )} a^{3} c e^{\left (4 i \, f x + 4 i \, e\right )} + {\left (1728 i \, A + 576 \, B\right )} a^{3} c e^{\left (2 i \, f x + 2 i \, e\right )} + {\left (384 i \, A + 128 \, B\right )} a^{3} c\right )} \sqrt {\frac {c}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}}{315 \, {\left (f e^{\left (8 i \, f x + 8 i \, e\right )} + 4 \, f e^{\left (6 i \, f x + 6 i \, e\right )} + 6 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 4 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.42, size = 121, normalized size = 0.84 \[ \frac {2 i a^{3} \left (\frac {i B \left (c -i c \tan \left (f x +e \right )\right )^{\frac {9}{2}}}{9}+\frac {\left (-5 i B c +c A \right ) \left (c -i c \tan \left (f x +e \right )\right )^{\frac {7}{2}}}{7}+\frac {\left (-4 \left (-i B c +c A \right ) c +4 i B \,c^{2}\right ) \left (c -i c \tan \left (f x +e \right )\right )^{\frac {5}{2}}}{5}+\frac {4 \left (-i B c +c A \right ) c^{2} \left (c -i c \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{3}\right )}{f \,c^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.35, size = 104, normalized size = 0.72 \[ \frac {2 i \, {\left (35 i \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {9}{2}} B a^{3} + 45 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {7}{2}} {\left (A - 5 i \, B\right )} a^{3} c - 252 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {5}{2}} {\left (A - 2 i \, B\right )} a^{3} c^{2} + 420 \, {\left (-i \, c \tan \left (f x + e\right ) + c\right )}^{\frac {3}{2}} {\left (A - i \, B\right )} a^{3} c^{3}\right )}}{315 \, c^{3} f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 14.08, size = 335, normalized size = 2.33 \[ -\frac {\left (\frac {a^3\,c\,\left (A-B\,1{}\mathrm {i}\right )\,16{}\mathrm {i}}{5\,f}+\frac {a^3\,c\,\left (A-B\,3{}\mathrm {i}\right )\,16{}\mathrm {i}}{5\,f}\right )\,\sqrt {c+\frac {c\,\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1}}}{{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^2}-\frac {\left (\frac {a^3\,c\,\left (A-B\,1{}\mathrm {i}\right )\,16{}\mathrm {i}}{9\,f}-\frac {a^3\,c\,\left (A+B\,1{}\mathrm {i}\right )\,16{}\mathrm {i}}{9\,f}\right )\,\sqrt {c+\frac {c\,\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1}}}{{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^4}+\frac {\left (\frac {64\,B\,a^3\,c}{7\,f}+\frac {a^3\,c\,\left (A-B\,1{}\mathrm {i}\right )\,16{}\mathrm {i}}{7\,f}\right )\,\sqrt {c+\frac {c\,\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1}}}{{\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )}^3}+\frac {a^3\,c\,\left (A-B\,1{}\mathrm {i}\right )\,\sqrt {c+\frac {c\,\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}\,1{}\mathrm {i}-\mathrm {i}\right )\,1{}\mathrm {i}}{{\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1}}\,16{}\mathrm {i}}{3\,f\,\left ({\mathrm {e}}^{e\,2{}\mathrm {i}+f\,x\,2{}\mathrm {i}}+1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ - i a^{3} \left (\int i A c \sqrt {- i c \tan {\left (e + f x \right )} + c}\, dx + \int \left (- 2 A c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )}\right )\, dx + \int \left (- 2 A c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{3}{\left (e + f x \right )}\right )\, dx + \int \left (- 2 B c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{2}{\left (e + f x \right )}\right )\, dx + \int \left (- 2 B c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{4}{\left (e + f x \right )}\right )\, dx + \int \left (- i A c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{4}{\left (e + f x \right )}\right )\, dx + \int i B c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan {\left (e + f x \right )}\, dx + \int \left (- i B c \sqrt {- i c \tan {\left (e + f x \right )} + c} \tan ^{5}{\left (e + f x \right )}\right )\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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